If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(x^2)/3-((5*x^1)/3) = 50 // - 50
(x^2)/3-((5*x^1)/3)-50 = 0
(x^2)/3+(-5/3)*x-50 = 0
1/3*x^2-5/3*x-50 = 0
DELTA = (-5/3)^2-(-50*1/3*4)
DELTA = 625/9
DELTA > 0
x = ((625/9)^(1/2)+5/3)/(1/3*2) or x = (5/3-(625/9)^(1/2))/(1/3*2)
x = 15 or x = -10
x in { -10, 15 }
| 4-x^2=1-x^2 | | 8x^2=15-4x | | D=-3E+4F | | r=6s | | 6+r=114 | | 30-v=255 | | 5y^2+8y+1=0 | | y-33=147 | | 9/17x-7/17x | | 3/2x-1/2=x/6-7/4 | | 7+4x=6-4x | | 25y=15+75y | | y-14=66 | | 8^5x=1/16 | | 6x=9(9) | | 21=4/9x-7 | | -1.3x^2+4x+1.75=0 | | 3x+5=12-4x | | 9i-18=61 | | 9i-18=61 | | 536/22 | | 2(7(x-5))= | | -4(p+3)+4=20 | | 15+2k=4y+5 | | 4x^2-48x+y^2=-140 | | 5c-3=5c+17 | | 7/4y=49 | | 16w=240 | | 4x^2-48+y^2=-140 | | 3.2(x+15)=2.4x-2.7+1.4x | | x-62=123 | | Sin(4x)-cos(6x)=1 |